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Coordination Complexes

CuS O 4 when ...

Question

$C u S O_{4}$ when reacts with $K C N$ forms $C u C N$ which is insoluble in water. It is soluble in excess of $K C N$ due to the formation of the following complex

K_{2} [C u {(C N)}_{4}]

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K_{3} [C u {(C N)}_{4}]

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C u C N_{2}

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C u [K C u {(C N)}_{4}]

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Solution

The correct option is A $K_{3} [C u {(C N)}_{4}]$
$C u S O_{4}$ reacts with $K C N$ and gives a white precipitate of cuprous cyanide and cyanogen gas. The cuprous cyanide dissolves in excess of $K C N$ forming $K_{3} [C u {(C N)}_{4}]$
$C u S O_{4} + 2 K C N ⟶ K_{2} S O_{4} + C u {(C N)}_{2}$
$2 C u {(C N)}_{2} ⟶ 2 C u C N i n s o l u b l e + C N - C N c y a n o g e n$
$C u C N + 3 K C N ⟶ K_{3} [C u {(C N)}_{4}] s o l u b l e$

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