CuSO4.5H2O(s) ⇌ CuSO4.3H2O(s) + 2H2O(g); kp = 4 104 atm2. If the vapour pressure of water is 38 torr then percentage of relative humidity is : (Assume all data at constant temperature)
A
4
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B
10
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C
40
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D
None of these
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Solution
The correct option is C 40 KP=(PH2O)2PH2O=√KP=√4×10−4=2×10−2