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Question

CuSO45H2O(s) CuSO4 3H2O(s) + 2H2O(g); Kp = 4×104 atm2 if the vapour pressure of water is 38 torr then percentage of relative humidity is: ( Assume all data at constant temperature)

A
4
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B
10
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C
40
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D
none of these
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Solution

The correct option is C 40
Kp=P2H2O=4×104
PH2O=2×102atm0.02atm
P1H2O=38atm38760atm120atm0.05atm
%Relativehumidity=PH2OP1H2O0.020.05=25×10040%
Option C is correct.

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