Question

$CuS{O}_4$ is paramagnetic while $ZnS{O}_4$ is diamagnetic because:

• A. $C{u}^{2+}$ ion has $3d^9$ configuration while $Z{n}^{2+}$ ion has $3d^{10}$ configuration.
• B. $C{u}^{2+}$ ion has $3d^5$ configuration while $Z{n}^{2+}$ ion has $3d^6$ configuration.
• C. $C{u}^{2+}$ has half filled orbitals while $Z{n}^{2+}$ has fully filled orbitals.
• D. $CuS{O}_4$ is blue in colour while $ZnS{O}_4$ is white.

Answer 1

Answer: (A)

$C{u}^{2+}$ ion has $3d^9$ configuration while $Z{n}^{2+}$ ion has $3d^{10}$ configuration.

$CuS{O}_4$ has $C{u}^{+2}$ ion which has electronic configuration of $\left[Ar\right]3d^{9}4s^0$ while in $ZnS{O}_4$ ,$Z{n}^{+2}$ has $\left[Ar\right]3d^{10}4s^0$ configuration.