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Byju's Answer

Standard XII

Chemistry

Introduction to Oxidation and Reduction

CuSO4 reacts ...

Question

$C u S O_{4}$ reacts with KCN solution and forms:

C u (C N)

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C u (C N)_{2}

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K_{3} [C u (C N)_{4}]

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K_{4} [C u (C N)_{6}]

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Solution

The correct option is D $K_{3} [C u (C N)_{4}]$
$C u S O_{4} + K C N \to K_{3} [C u (C N)_{4}]$

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Similar questions

Which compound is formed when an excess of $K C N$ is added to an aqueous solution of copper sulphate?

C u S O_{4}

decolourises on addition of KCN, the product is

Q. Select correct answer:

(I)

K F

combines with

H F

to form

K H F_{2}

. The compound contains the species:
(a)

K^{+}, F^{-}

and

H^{+}

(b)

K^{+}, F

and

H F

(c)

K^{+}

and

[H F_{2}]^{-}

(d)

[K H F]^{+}

and

F^{-}

(II) Which compound is formed when excess of

K C N

is added to aqueous solution of copper sulphate?
(a)

C u (C N)_{2}

(b)

K_{2} [C u (C N)_{4}]

(c)

K [C u (C N)_{2}]

(d)

K_{3} [C u (C N)_{4}]

C u S O_{4}

when reacts with

K C N

forms

C u C N

which is insoluble in water. It is soluble in excess of

K C N

, due to formation of the following complex:

Q. If

C u^{2 +}

and

C d^{2 +}

both are present, it is difficult to analyse. A scheme to analyse in a mixture is given below.
KCN forms complex with

C u^{2 +}

and

C d^{2 +}

C u^{2 +} + 2 C N^{-} ⟶ C u (C N)_{2}

C u (C N)_{2} ⟶ 2 C u C N ↓ + (C N)_{2}

C u C N + 3 K C N K_{3} C u (C N)_{4}] s t a b l e C d^{2 +} + K C N ⟶ K_{2} [C d (C N)_{4}] u n s t a b l e

when

H_{2} S

gas is passed, unstable complex of

C d^{2 +}

gives yellow ppt

[C d (C N)_{4}]^{2 -} ⇌ C d^{2 +} + 4 C N^{-}

C d^{2 +} + S^{2 -} ⟶ C d S y e l l o w ↓

If true enter 1, else enter 0.

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CuSO4 reacts with KCN solution and forms:

The correct option is D K3[Cu(CN)4]CuSO4+KCN→K3[Cu(CN)4]

$C u S O_{4}$ reacts with KCN solution and forms:

The correct option is D $K_{3} [C u (C N)_{4}]$
$C u S O_{4} + K C N \to K_{3} [C u (C N)_{4}]$