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Standard X

Chemistry

Laboratory Preparation of Ammonia

CuSO4 reacts ...

Question

$C u S O_{4}$ reacts with $N H_{4} O H$ to give deep blue complex of :

copperammonium sulphate

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copperammonium hydroxide

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both (A) and (B)

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none of these

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Solution

The correct option is A copperammonium sulphate
$C u S O_{4}$ reacts with $N H_{4} O H$ to give deep blue complex of copperammonium sulphate.
$C u S O_{4} + 4 N H_{4} O H ⟶ [C u {(N H_{3})}_{4}] S O_{4} + 4 H_{2} O$

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Similar questions

Q. A metal

^{'} M^{'}

reacts with nitrogen gas to give

^{'} M_{3} N^{'}

^{'} M_{3} N^{'}

on heating at high temperature gives back

^{'} M^{'}

and on reaction with water produces gas

^{'} B^{'}

. Gas

^{'} B^{'}

reacts with aqueous solutions of

C u S O_{4}

to form a deep blue compound.

^{'} M^{'}

and

^{'} B^{'}

respectively are:

Blue solution of $C u S O_{4}$ when reacts with excess of $K C N$ gives colourless solution due to the :

Q. Three cations

A, B, C

are allowed to react with ammonium hydroxide solution.

A

and

B

produce a dirty green precipitate and a reddish brown precipitate respectively, both of which do not dissolve on further addition of

{N H}_{4} O H

C

gives pale blue colour precipitate with less amount of ammonium hydroxide and on further addition of

{N H}_{4} O H

, precipitate becomes soluble and deep blue colour solution is formed:

Q. Which of the following compounds after mixing can produce blue colouration?
I.

K_{4} [F e (C N)_{6}]

and

F e C l_{3}

solution
II.

N H_{4} O H

and

C u S O_{4}

solution
III. Adding anhydrous

C u S O_{4}

to water
IV.

N H_{4} O H + N i S O_{4}

solution

Q. Which of the following statements is wrong about

C u S O_{4}

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CuSO4 reacts with NH4OH to give deep blue complex of :

The correct option is A copperammonium sulphateCuSO4 reacts with NH4OH to give deep blue complex of copperammonium sulphate.CuSO4+4NH4OH⟶[Cu(NH3)4]SO4+4H2O

$C u S O_{4}$ reacts with $N H_{4} O H$ to give deep blue complex of :

The correct option is A copperammonium sulphate
$C u S O_{4}$ reacts with $N H_{4} O H$ to give deep blue complex of copperammonium sulphate.
$C u S O_{4} + 4 N H_{4} O H ⟶ [C u {(N H_{3})}_{4}] S O_{4} + 4 H_{2} O$