Cyclic hydrocarbon ′A′ has all the carbon and hydrogen atoms in a single plane. All the carbon carbon bonds have the same length, less than 1.54A∘, but more than 1.34A∘. The bond angle will be
A
109∘28′
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B
100∘
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C
180∘
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D
120∘
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Solution
The correct option is D120∘ All the properties mentioned in the question suggest that is a benzene molecule. Since in benzene all carbons are sp2− hybridized. therefore. C−C−Cangle is120∘.