Cyclopropane rearranges to form propene as- - C H 3 -CH-C H 2This follows first order kinetics- The rate constant is 2-714- 10 -3 sec -1- The initial concentration of cyclopropane is 0-29 M- What will be the concentration of cyclopropane after 100 sec-

The correct option is B 0.22 M A= A _ 0 e ^ kt =0.29 e ^ 2.714× 10 ^ 3 × 100 =0.22M ...

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First Order Reaction

Cyclopropane ...

Question

Cyclopropane rearranges to form propene as:
$Δ ⟶ C H_{3} - C H = C H_{2}$
This follows first order kinetics. The rate constant is $2.714 \times 10^{- 3} {s e c}^{- 1}$ . The initial concentration of cyclopropane is $0.29$ $M$ . What will be the concentration of cyclopropane after $100$ sec?

0.035

M

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0.22

M

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0.145

M

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0.0018

M

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Solution

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△ \to C H_{2} - C H = C H_{2}

2.714 \times 10^{- 3} s e c^{- 1}

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1 \times 10^{- 2} {sec}^{- 1}

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