$d^{6}$ configuration will result in total spin of:

\frac{3}{2}

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\frac{1}{2}

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2

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1

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Solution

The correct option is D $2$
Configuration of $d^{6}$ has 4 unpaired electron
Total spin value $= \frac{n o . o f u n p a i r e d e l e c t r o n}{2}$
$∴ t o t a l s p i n v a l u e = \frac{4}{2} = 2$

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