D and F are mid-points of sides AB and AC of ΔABC. A line through F and parallel to AB meets BC at point E. If EF = 3.8 cm, AB =
Any 2 sides of ∆ 1 and 1 angle should be equal to any 2 sides and 1 angle of ∆ 2
It is given that EF∥AB
Using converse of mid-point theorem,
E is the mid point of BC. [F is mid point of AC and EF∥AB]
⇒EF=12AB
or, AB=2EF=2×3.8 cm=7.6 cm