1
You visited us
1
times! Enjoying our articles?
Unlock Full Access!
Byju's Answer
Standard XII
Mathematics
Determinant
D= 18 40 ...
Question
D
=
∣
∣ ∣
∣
18
40
89
40
89
198
89
198
440
∣
∣ ∣
∣
=
A
1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
−
1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
zero
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is
B
−
1
We have,
D
=
∣
∣ ∣
∣
18
40
89
40
89
198
89
198
440
∣
∣ ∣
∣
D
=
18
×
(
89
×
440
−
198
2
)
−
40
×
(
40
×
440
−
198
×
89
)
+
89
×
(
40
×
198
−
89
2
)
D
=
18
×
(
39160
−
39204
)
−
40
×
(
17600
−
17622
)
+
89
×
(
7920
−
7921
)
D
=
18
×
(
−
44
)
−
40
×
(
−
22
)
+
89
×
(
−
1
)
D
=
−
792
+
880
−
89
D
=
−
1
Therefore, the value of the determinant is
−
1
.
Suggest Corrections
0
Similar questions
Q.
Using properties of determinants or otherwise evaluate
∣
∣ ∣
∣
18
40
89
40
89
198
89
198
440
∣
∣ ∣
∣
Q.
Using properties of determinants, the negative of
∣
∣ ∣
∣
18
40
89
40
89
198
89
198
440
∣
∣ ∣
∣
would be
Q.
Using properties of determinants, the value of determinant
∣
∣ ∣
∣
18
40
89
40
89
198
89
198
440
∣
∣ ∣
∣
is obtained as:
Q.
If two zeros x
3
+ x
2
− 5x − 5 are
5
and
-
5
, then its third zero is
(a) 1
(b) −1
(c) 2
(d) −2