Question

Question 93 (d)

Find a rational number exactly halfway between
$\frac{1}{15}and\frac{1}{12}$

Answer 1

Given rational numbers are $\frac{1}{15}and\frac{1}{12}$
Here,$a=\frac{1}{15}andb=\frac{1}{12}\therefore \frac{a+b}{2}=\frac{\frac{1}{15}+\frac{1}{12}}{2}=\frac{\frac{1\times 4}{15\times 4}+\frac{1\times 5}{12\times 5}}{2}=\frac{\frac{4}{60}+\frac{5}{60}}{2}=\frac{\frac{4+5}{60}}{2}=\frac{9}{60\times 2}=\frac{9}{120}=\frac{3}{40}$