Question 66 (d)
Find the value of the given polynomial at a = -2 and b = 3.
a3−3a2b+3ab2−b3
Given, a = -2 and b = 3 So, putting a = -2 and b = 3 in the given expression, we get a3−3a2b+3ab2−b3=(−2)3−3(−2)2(3)+3(−2)(3)2−(3)3=−8−36−54−27=−125
Find the value of a3−b3−3a2b+3ab2 , when a = 5 and b = 3.
Which of the following is an expansion of the identity (a–b)3?