Question

Question 4(d)

Find using distributive property:

$4275\times 125$

Answer 1

$4275\times 125$

125 can be represented as (100 + 20 + 5).

Now using the distributive property:

a×(b+c+d)=(a×b)+(a×c)+(a×d), we get,

$4275\times 125=4275\times (100+20+5)$
= $(4275\times 100)+(4275\times 20)+(4275\times 5)$
= $427500+85500+21375$
= $534375$