Question

D- glucose, on treating with methanol in the presence of dry $HCl$ gives methyl glucoside according to the following reaction:


Mention true (T) and False (F) from the following statements:
$S_1:$ The glucosides do not reduce fehling's solution.
$S_2:$ The glucosides do not react with hydrogen cyanide or hydroxylamine.
$S_3:$ Behaviour of glucosides as stated in $S_1$ and $S_2$ indicates the absence of free $-CHO$ group.
$S_4:$ The two forms of glucosides are enantiomers.

• A. $TTFF$
• B. $FTTT$
• C. $TTTF$
• D. $TFTF$

Answer 1

The correct option is C $TTTF$

Glucosides do not reduce Fehling's solution and do not react with $HCN$ or $N{H}_{2}OH$ that indicate that the $-CHO$ group is absent.
$S_1,S_2\text{and}{S}_3$ are true but $S_4$ is false because the glucosides are not mirror images of each other and hence they can be considered as diastereomers.