Question

Question 91 (d)

In the following case, write the rational number whose numerators and denominator are respectively as under:
$25+15and81÷40$

Answer 1

Given, $25+15and81÷40$
Let numeerator, $p=25+15=40$
and denominator $q=81÷40=\frac{81}{40}$
Hence, rational number $=\frac{p}{q}=40÷\frac{81}{40}=40\times \frac{40}{81}$ [$\because$ reciprocal of $\frac{81}{40}=\frac{40}{81}$]
$=\frac{1600}{81}$