D is a real number with non terminating digits a1 and a2 after the decimal point. Let D=0,a1a2a1a2........ with a1&a2 both not zero which of the following when multiplied by D will necessarily give an integer ?
A
99
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B
18
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C
125
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D
75
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Solution
The correct option is A99 its straight question give D=0.abababab(say−1) Multiply both sides by 100i.e. 100D=ab.abababab(say−2) now subtract 1 from 2. That gives 99D=ab=>D=ab/99 hence it should be multiplied by 99k to get an integer ab.