D - G - S reaction - dT- G - H - T - S- G - H - T d - G - dT PThe temperature coefficient of the e-m-f of a cell- dE - dT P is given by-A- - S - nF - SB- n- S - nF TD- nF - S

The correct option is A Δ SnFd(Δ G) nbsp; = Δ S dT Δ G = Δ H TΔ S Δ G = Δ H + T d(Δ G)/dT Δ G = Δ H + T d( nFE)/dT Δ G = Δ H nFT dE/dT dE/dT = Δ G Δ H ...

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Byju's Answer

Standard XII

Chemistry

Gibb's Free Energy

d Δ G =-Δ S r...

Question

$d (Δ G) = - (Δ S_{reaction}) . d T$
$Δ G = Δ H - T Δ S$
$Δ G = Δ H + T {(\frac{d (Δ G)}{d T})}_{P}$
The temperature coefficient of the e.m.f of a cell, ${(\frac{d E}{d T})}_{P}$ is given by:

\frac{n F}{Δ S}

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\frac{Δ S}{n F}

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\frac{Δ S}{n F T}

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- n F E

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Solution

The correct option is B $\frac{Δ S}{n F}$
$d (Δ G) = - Δ S d T$

$Δ G = Δ H - T Δ S$

$Δ G = Δ H + T \frac{d (Δ G)}{d T}$

$Δ G = Δ H + T \frac{d (- n F E)}{d T}$

$Δ G = Δ H - n F T \frac{d E}{d T}$

$\frac{d E}{d T} = \frac{Δ G - Δ H}{- n F T}$

$\frac{d E}{d T} = \frac{- T Δ S}{- n F T}$

$\frac{d E}{d T} = \frac{Δ S}{n F}$

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Similar questions

d (Δ G) = - (Δ S_{reaction}) . d T

Δ G = Δ H - T Δ S

Δ G = Δ H + T {(\frac{d (Δ G)}{d T})}_{P}

The temperature coefficient of the e.m.f of a cell,

{(\frac{d E}{d T})}_{P}

is given by:

d (Δ G) = - (Δ S_{reaction}) . d T

Δ G = Δ H - T Δ S

Δ G = Δ H + T {(\frac{d (Δ G)}{d T})}_{P}

Calculate

Δ S

for the given cell reaction in the previous question.

d (Δ G) = - (Δ S_{reaction}) . d T

Δ G = Δ H - T Δ S

Δ G = Δ H + T {(\frac{d (Δ G)}{d T})}_{P}

300 K, Δ H

for the reaction,

Z n_{(S)} + 2 A g C l_{(S)} \to Z n C l_{2_{(a q)}} + 2 A g_{(S)}

- 218 kJ/mol

while the e.m.f of the cell is

1.015 V

{(\frac{d E}{d T})}_{P}

of the cell is:

Q. The cell potential

(E_{c e l l})

of a reaction is related as

Δ G = n F E_{c e l l}

, where

Δ G

represents maximum useful electrical work.
n = no. of moles of electrons exchanged during the reaction.
For reversible cell reaction

d (Δ G) = (Δ V) d p - (Δ S) d T

At const. P,

d (Δ G) = - (Δ S) d T

At const. P,

Δ G = Δ H - T Δ S

. (1)

∴ Δ G = Δ H + T {(\frac{d (Δ G)}{Δ T})}_{P}

. (2)

{(\frac{d E_{c e l l}}{d T})}_{p}

is known as temperature coefficient of the emf of the cell.

The temperature coefficient of the emf the cell,

{(\frac{d E}{d T})}_{p}

is given by

d (Δ G) = - (Δ S_{reaction}) . d T

Δ G = Δ H - T Δ S

Δ G = Δ H + T {(\frac{d (Δ G)}{d T})}_{P}

Calculate

Δ S

for the given cell reaction in the previous question.

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d(ΔG)=−(ΔSreaction).dT ΔG=ΔH−TΔS ΔG=ΔH+T(d(ΔG)dT)P The temperature coefficient of the e.m.f of a cell, (dEdT)P is given by:

The correct option is B ΔSnFd(ΔG) = −ΔS dT ΔG = ΔH − TΔS ΔG = ΔH + T d(ΔG)dT ΔG = ΔH + T d(−nFE)dT ΔG = ΔH − nFT dEdT dEdT = ΔG − ΔH−nFT dEdT = −TΔS−nFT dEdT = ΔSnF

$d (Δ G) = - (Δ S_{reaction}) . d T$
$Δ G = Δ H - T Δ S$
$Δ G = Δ H + T {(\frac{d (Δ G)}{d T})}_{P}$
The temperature coefficient of the e.m.f of a cell, ${(\frac{d E}{d T})}_{P}$ is given by: