$d -$ orbital involved in hybridization of $P F_{2} C l_{3}$ is:

d_{x y}

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d_{z^{2}}

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d_{z x}

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d_{x^{2} - y^{2}}

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Solution

The correct option is B $d_{z^{2}}$
$P F_{2} C l_{3}$ has $s p^{3} d$ hybridisation. In $s p^{3} d$ hybridisation the $d_{z^{2}}$ orbital takes part. So option B is correct.

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Similar questions

The d-orbital involved in ${s p}^{3} d$ hybridization is

d

d

d_{x^{2} - y^{2}}, d_{z}^{2}

d_{x y}

d_{y z}

d_{z x}

s p^{3} d

d

d s p^{2}

d_{x^{2} - y^{2}}

$d_{x^{2} - y^{2}}$ orbital is not involved in which of the following hybridization?

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