Question

$d-$orbital involved in hybridization of ${SF}_4$ is:

• A. $d_{xy}$
• B. $d_{yz}$
• C. $d_{x^2-y^2}$
• D. $d_{z^2}$

Answer 1

The correct option is D $d_{z^2}$

$S$ atom in $S{F}_4$ is bonded to four Fluorine atoms and has one lone pair ($S$ has 6 valence electrons; four of them went in bonding with four Fluorine atoms while the other two remained as a lone pair on $S$ atom). All of them are in hybridized orbitals. There are five such orbitals. So the hybridization is $s{p}^{3}d.$ The $d-$orbital involved in hybridization of $S{F}_4$ is $d_{z^2}$. Always $d_{z^2}$ takes part in $s{p}^{3}d$ hybridisation.