Question

$d\pi -p\pi$ bond present in:

• A. $C{O}_3^{2-}$
• B. $P{O}_4^{3-}$
• C. $N{O}_3^{-}$
• D. $N{O}_2^{-}$

Answer 1

The correct option is B $P{O}_4^{3-}$

In $P{O}_4^{3-}$, $P$ atom has vacant $3d$ - orbitals (as $P$ belongs to third period) and it can form $d\pi -p\pi$ bond with $2p$ orbital of $O$. whereas $N$ and $C$ have no vacant $d$ orbital (as they belongs to second period) in their valence shell and so cannot form such bond.