The correct options are
A sp3d2
B sp3d (sq. pyramidal)
C dsp2
D sp3d3
Orbitals which involves in their respective hybridization:
sp3d → spxpypzdx2−y2
dsp3 → dx2−y2spxpypz
sp3d2 → spxpypzdx2−y2dz2
sp3d3 → spxpypzdx2−y2dz2dxy
Hence, options A, B, C and D are correct.