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Question

ΔABC is an isosceles triangle in which AB = AC. Show that ∠B = ∠C.

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Solution


Given the ΔABC is an isosceles triangle and AB = AC

Let D be the mid point of BC; Join A to D.

Now in ΔABD and ΔACD

AB = AC (given)

BD = DC (construction)

AD = AD (common)

ΔABD ΔACD (SSS congruence rule)

∠B = ∠C (CPCT)

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