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Daily demand ...

Question

Daily demand for transistors is has the following probability distribution.
Demand: 1 2 3 4 5 6
Probability: 0.10 0.15 0.20 0.25 0.18 0.12
The expected daily demand for transistors is

2.25

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5.4

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3.62

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3.3

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Solution

The correct option is B 3.62
$D e m a n d (x) Pr o b a b i l i t y (p) x (p)$
$1 0.10 0.1$
$2 0.15 0.3$
$3 0.20 0.6$
$4 0.25 1.0$
$5 0.18 0.9$
$6 0.12 0.72$
$T he expected daily demand = \sum x (p)$
$= 0.1 + 0.3 + 0.6 + 1.0 + 0.9 + 0.72$
$= 3.62$

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