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Question

DC, if MN = 15 cm and AB = 23 cm.
194316_f23aaf39975b4276bb5796916a9c4b12.png

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Solution

Join BD, let BD and MN meet at Q. Since, M is the mid point of AD and N is the mid point of BC. So by mid point theorem, AB II MN IICD
In , BDC and BQN,
B=B (Common)
BDC=BQN (Corresponding angles of parallel lines)
BCD=BNQ (Corresponding angles of parallel lines)
thus, BDCBQN
Thus, BDQB=DCQN
2=DCQN (Q is the mid point of BD)
QN=12DC
Similarly, QM=12AB
Hence, QM+QN=12(AB+DC)
MN=12(AB+CD)
Hence, 2×15=23+CD
CD=3023=7cm

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