Question

DDT, an insecticide harmful to fish, birds, and humans, is produced by the following reaction:
$2C_6{H}_{5}Cl\left(chlorobenzene\right)+C_{2}HOC{l}_3\left(chloral\right)\to C_{14}{H}_{9}C{l}_5\left(DDT\right)+H_{2}O$
In a government lab, 1142 g of chlorobenzene is recated with 485 g of chloral.
If the actual yield of DDT is 200.0 g, what is the percent yield?

Answer 1

% of yield $=\left[\frac{\text{actual yield}}{\text{theoretical yield}}\right]100$%

$=\left[\frac{200}{11170}\right]100=17.1$% .