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Question

DE || BC and AD+DB = 3+5. If AC= 5.6, find AE. ALso if AC= 4.8cm, find AE

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Solution

Dear student
Given: in triangle ABC, DEBC,AD+DB=3+5,AC=5.6We know that,If a line is drawn parallel to one side of triangle intersecting the othertwo sides, then it divides the two sides in the same ratio.i.e., ADDB=AEAC35=AEAC-AE35=AE5.6-AE16.8-3AE=5AEAE=2.1 cmIf AC=4.8cm, then35=AEAC-AE35=AE4.8-AE14.4-3AE=5AEAE=1.8 cm
Regards

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