Question

de-Broglie wavelength associated with an electron revolving in the $n^{th}$ state of hydrogen atom is directly proportional to

• A. $n$
• B. $\frac{1}{n}$
• C. $n^2$
• D. $\frac{1}{n^2}$

Answer 1

The correct option is A $n$

$V_n=2.165\times {10}^6\left(\frac{z}{n}\right)$

$V_n\propto \frac{1}{n}$

$m{V}_n\propto \frac{1}{n}$

$\therefore \lambda =\frac{h}{m{V}_n}\propto n$