de-Broglie wavelength of a body of mass m and kinetic energy E is given by

λ = \frac{h}{m E}

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λ = \frac{\sqrt{2 m E}}{h}

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λ = \frac{h}{2 m E}

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λ = \frac{h}{\sqrt{2 m E}}

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Solution

The correct option is D $λ = \frac{h}{\sqrt{2 m E}}$
de-Broglie wavelength of a body of mass m and kinetic energy E is given by $λ = \frac{h}{\sqrt{2 m E}}$

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Similar questions

m

E

\frac{h}{\sqrt{2 m E}}

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m = 9.1 \times 10^{- 31} kg, h = 6.6 \times 10^{- 34} Js

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h = 6.6 \times 10^{- 34} J - s, m_{e} = 9.1 \times 10^{- 31} k g

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