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Question

de-Broglie wavelength of atom at TK absolute temperature will be

A
hmKT
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B
h3mKT
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C
2mKTh
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D
2mKT
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Solution

The correct option is B h3mKT
de-Broglie wavelength λ=hmv
Kinetic energy of the atom K.E=12mv2=32KT
mv=3mKT
Thus we get λ=h3mKT
So, option B is correct.

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