The sets are given as,
A={ x:x∈R and x satisfy x 2 −8x+12=0 }
B={ 2,4,6 }
C={ 2,4,6,8... }
D={ 6 }
Solve the quadratic equation of set A to find its elements.
x 2 −8x+12=0 x 2 −6x−2x+12=0 x( x−6 )−2( x−6 )=0
Solve the above equation to find the roots of x.
x=2,6
Thus,
A = { 2,6 }
Set A is the subset of set B, if all the elements of A are in B.
For set A,
All the elements of set A are in set B and C.
Therefore, A is a subset of B, that is,
A ⊂ B
And, Ais a subset of C, that is,
A ⊂ C
For set B,
All the elements of set B are in set C.
Therefore, B is a subset of C, that is,
B ⊂ C
For set C,
All the elements of set C are not in any set.
Therefore, C is not a subset of any set.
For set D,
All the elements of set D are in set A, B and C.
Therefore,
D is a subset of A, that is,
D ⊂ A
D is a subset of B, that is,
D ⊂ B
And, D is a subset of C, that is,
D ⊂ C