Given data:
A={x:x∈R and x satisfy x2−8x+12=0}
B={2,4,6}, C={2,4,6,8,....}, D={6}
Step 1 : Solve for set A
{x:x∈R and x satisfy x2−8x+12=0}
On solving x2−8x+12=0
⇒x2−6x−2x+12=0
⇒x(x−6)−2(x−6)=0
⇒(x−6)(x−2)=0
⇒x=2,6
Thus A={2,6},B={2,4,6},C={2,4,6,8,...},D={6}
Since all elements of A are in B,
So A is a subset of B i.e., A⊂B
All elements of A are in C⇒A⊂C
Step 2: Check for set B
∵ All elements of set B are in set C
∴B⊂C
Step 3: Clearly, C is not a subset of any other given set.
Step 4: Check for set D
All elements of D are in A
All elements of D are in B
All elements of D are in C
∴D⊂A,D⊂B and D⊂C
Final answer:
Thus, A⊂B,A⊂C,B⊂C,D⊂A,D⊂B and D⊂C