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Question

Decomposition of H2O2 is a first order reaction. A solution of H2O2 labelled as 20 volumes was left open. Due to this, some H2O2 decomposed. To determine the new volume strength after 6 hours, 10 mL of this solution was diluted to 100 mL. 10 mL of this diluted solution was titrated against 25 mL of 0.025 N KMnO4 solution under acidic conditions. The rate constant for decomposition of H2O2 is:

A
8.1×105Ms1
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B
8.64×106Ms1
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C
9.23×106Ms1
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D
9.65×106Ms1
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Solution

The correct option is A 8.1×105Ms1
Equivalent of H2O2 after dilution =251000×0.025=6.25×104
Normality =6.25×10410×1000=0.0625 N
Normality before dilution =0.0625×10=0.625 N
Volume strength =5.6× normality =5.6×0.625=3.5 N
The integrated rate law for the first order reaction is k=2.303tlog[A]0[A]t=2.3036×3600log203.5=8.1×105Ms1

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