Decreasing $(- I)$ effect of given groups is $I . C N$ $I I . N O_{2}$ $I I I . N H_{2}$ $I V . F$

I I > I > I V > I I I

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

I I > I I I > I V > I

No worries! We‘ve got your back. Try BYJU‘S free classes today!

I I I > I I > I V > I

No worries! We‘ve got your back. Try BYJU‘S free classes today!

I I I > I I > I > I V

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $I I > I > I V > I I I$
Inductive effect ( $I$ ) is the effect in which polarization of sigma bond takes place due to the polarization of adjacent sigma bond due to the presence of more electronegative group.
The electron withdrawing group show $- I$ effect and electron donating group show $+ I$ inductive effect.
Thus the correct order of $- I$ is: $N O_{2} > C N > F > N H_{2}$

Suggest Corrections

Similar questions

- I

- C N

- N O_{2}

- N H_{2}

- F

(i) C N (i i) N O_{2} (i i i) N H_{2} (i v) F

- C \equiv N

- C O N H_{2}

- N H_{2}

- S O_{3} H

The order of -I power (-ve inductive effect ) of the following functional groups will be:

(i) $- S O_{3} H$

(ii) $- C l$

(iii) $- N H_{2}$

(iv) $- H$

Join BYJU'S Learning Program