Decreasing order of basicity is? (i) CH3NH2 (ii) C6H5CH2NH2 (iii) p−CH3O−C6H4−NH2 (iv) m−CH3O−C6H4−NH2
A
I > II > III > IV
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B
II > IV > I > III
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C
II > IV > III > I
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D
IV > I > II > III
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Solution
The correct option is A I > II > III > IV
Basicity depends upon the availability of the lone pair on the Natom. If the lone pair on N is more available then it makes it a better Lewis base and if the lone pair is less available it makes the amine a weak Lewis base. Tertiary amines are the most basic followed by secondary, primary and phenyl amines. Amides are still weaker than the phenyl amines and can be considered neutral.
Therefore, the correct answer will be option A) I>II>III>IV