Decreasing order of nucleophilicity is:

O H^{-} > N H_{2}^{-} > C H_{3} O^{-} > R N H_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

N H_{2}^{-} > O H^{-} > C H_{3} O^{-} > R N H_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

N H_{2}^{-} > C H_{3} O^{-} > O H^{-} > R N H_{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

C H_{3} O^{-} > N H_{2}^{-} > O H^{-} > R N H_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $N H_{2}^{-} > C H_{3} O^{-} > O H^{-} > R N H_{2}$
If the nucleophilic atoms are in the same row of periodic table, nucleophilicity is approximately in order of basicity. So, the order is $N H_{2}^{-} > C H_{3} O^{-} > O H^{-} > R N H_{2}$ .

Suggest Corrections

Similar questions

C H_{3} N H_{2}

C_{6} H_{5} C H_{2} N H_{2}

p - C H_{3} O - C_{6} H_{4} - N H_{2}

m - C H_{3} O - C_{6} H_{4} - N H_{2}

Arrange in decreasing order of basicity,

$H_{2} O, O H^{-}, C H_{3} O H, C H_{3} O^{-}$

(N H_{2}^{-}, C H_{3} C O O^{-}, O H^{-})

O H^{-}, N H_{2}^{-}, H C \equiv C^{⊝}

C H_{3} - C H_{2}^{⊝}

What is the decreasing order of strengths of the following bases?
$⊖ O H, N H_{2}^{⊖}, H - C \equiv C^{⊖}, a n d C H_{3} - C H_{2}^{⊖}$

Join BYJU'S Learning Program