Question

Decreasing order of stability of following alkenes is..
(i)${CH}_3-CH={CH}_2$
(ii)${CH}_3-CH=CH-{CH}_3$
(iii)${CH}_3-\underset{\stackrel{|}{{CH}_3}}{C}=CH-{CH}_3$
(iv)${CH}_3-\stackrel{\underset{|}{{CH}_3}}{C}=\stackrel{\underset{|}{{CH}_3}}{C}-{CH}_3$

• A. i>ii>iii>iv
• B. iv>iii>ii>i
• C. iii>iv>ii>i
• D. ii>iii>i>>iv

Answer 1

Answer: (B)

iv>iii>ii>i

Stability of alkenes is directly proportional to the number of R-groups attached to double bonded carbon atom.

Therefore more the number of R-groups, greater is the stability of alkene.

$\therefore \text{Correct order of stability is -}iv>iii>ii>i$