Deduce the structural formula of a compound, C10H10(A) that gives (B) on oxidation:
HOOC(B)−CH2−C|CH2−COOHH−CH2−COOH
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Solution
Degree of unsaturation =2n1−n2+22=20−10+22=6 Thus, there may be 6π bonds. Presence of three carboxylic acids confirm that there are three triple bonds in ′A′. (A)→HC≡C−CH2−C|CH2−C≡C−HH−CH2−C≡C−H.