Deduce the structure of $P F_{5}$ on the basis of VSEPR theory.

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Solution

The central atom P has 5 valence electrons in $P F_{5}$ and each electron form a covalent bond with one F atom. So, molecule has 5 bond pairs and the best possible molecular arrangement that keeps these five bond pairs maximally apart is trigonal bipyramidal shape having two axial bonds and three equatorial bonds.

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Deduce the structure of PF5 on the basis of VSEPR theory.

Deduce the structure of $P F_{5}$ on the basis of VSEPR theory.