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Question

ΔDEF~ΔABC.
If DE = 6 cm, EF = 10 cm, FD = 5 cm, and AB = 4 cm, find the perimeter of ΔABC.

[1 mark]

A
42 cm
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B
28 cm
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C
21 cm
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D
14 cm
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Solution

The correct option is D 14 cm
Given,
ΔDEFΔABC
DEAB=EFBC=FDCA=Perimeter of ΔDEFPerimeter of ΔABC

Perimeter of ΔDEF=DE+EF+FD= 6+10+5=21cm

64=21Perimeter of ΔABC
Perimeter of ΔABC=14 cm

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