Dear Student,
•Kinetic energy -
The energy possessed by virtua of its motion is said to be kinetic energy. SI unit of kinetic energy is joule (J).
K E = 1/2mv2
Derivation : we know that
W = f x s
but f = ma
W = mas......-> Eqn 1
By 3rd Eqn of motion
v2 = u2 + 2as
at rest u=0
v2 = 2as
as = 1/2 v2
Putting in Eqn 1
W = 1/2 mv2
Since work done is stored in kinetic energy.
so, K E = 1/2 mv2
• Potential Energy -
The energy possessed by virtua of its position is said to be potential energy. SI unit of potential energy is joule (J).
P E = mgh
Derivation: we know that
W = f x s ....Eqn 1
when the object of mass m is lifted at a height h then,
F = mg and
s = h
then Eqn 1 becomes
W = mgh
Since work done = P E
so, P E = mgh
Regards