Define enthalpy of sublimation. How is it related to enthalpy of fusion and enthalpy of vaporization?

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Solution

The enthalpy change that accompanies the conversion of one mole of solid directly into its vapour at constant temperature is called as enthalpy of sublimation.
$Δ_{s u b} H \to Δ_{f u s} H + Δ_{v a p} H$

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Enthalpy of sublimation of a substance is equal to
(a) enthalpy of fusion + enthalpy of vaporisation
(b) enthalpy of fusion
(c) enthalpy of vaporisation
(d) twice the enthalpy of vaporisation

Q. Define Enthalpy of vaporization.

Q. The sublimation energy of

I_{2} (s)

57.3 k J / m o l

and the enthalpy of fusion is

15.5 k J / m o l

. The enthalpy of vaporisation of

I_{2}

is:

Q. In the textbook the E value for copper is positive ,it is due to the sum of enthalpy of sublimation and ionization not balancing hydration enthalpy .My question is how the electrode potential dependent upon enthalpy of sublimation , ionization and hydration ?

Q. why is the enthalpy of vaporization and fusion of deuterium more than that of protium?

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Define enthalpy of sublimation. How is it related to enthalpy of fusion and enthalpy of vaporization?

The enthalpy change that accompanies the conversion of one mole of solid directly into its vapour at constant temperature is called as enthalpy of sublimation.ΔsubH→ΔfusH+ΔvapH

The enthalpy change that accompanies the conversion of one mole of solid directly into its vapour at constant temperature is called as enthalpy of sublimation.
$Δ_{s u b} H \to Δ_{f u s} H + Δ_{v a p} H$