Question

Define metallic bond. Iron has a body centred cubic unit cell with cell dimension of $286.65$pm . calculate the density of iron [Atomic mass of $Fe=56$]

Answer 1

Metallic bond is a type of chemical bond that occurs between atoms and metallic elements it is formed by the valance electrons moving freely through the metal lattice and positive charged metallic atoms .

Metallic bonds extended over the entire molecule structure.

Given $Fe$ has bcc unit $Z=2a=286.65pm,=286.65\times {10}^{-10}cm,M=56N_A=6.023\times {10}^{23}\text{atoms}$

Density is given by the equation, $d=\frac{Z\times M}{a^3\times N_A}=\frac{2\times 56}{{(286.65\times {10}^{-10})}^3\times 6.023\times {10}^{23}}$

$d=8.08gc{m}^{-3}$