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Stoichiometry

Define normal...

Question

Define normality. 6.3 gms of oxalic acid is present in 500 ml of soultion its normality is?

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Solution

$N o r m a l i t y = \frac{W e i g h t}{E q u i v a l e n t . W t} \times \frac{1000}{V o l u m e}$

$N o r m a l i t y = \frac{6.3}{63} \times \frac{1000}{500}$

$N o r m a l i t y = 0.2 N$

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