Question

Define Pythagoras theorem.

• A. In a right angled triangle , square of a hypotenuse is not equal to the sum of the squares of two sides.
• B. In a right-angled triangle, the square of a hypotenuse is equal to the sum of the squares of the other two sides.
• C. In a right angled triangle , hypotenuse is equal to the sum of two sides.
• D. In a triangle , square of a side is equal to the square of another side.

Answer 1

The correct option is B In a right-angled triangle, the square of a hypotenuse is equal to the sum of the squares of the other two sides.

In a right angled triangle ,square of hypotenuse (longest side) is equal to the sum of squares of other two sides.

In $△ABC$

${\left(AC\right)}^2{=\left(AB\right)}^2+{\left(BC\right)}^2$