L=ϕBI. . . . . . .(1)
Expression for the energy stored in a solenoid-
The induced emf in the coil is given by
e=−dϕBdt. . . . .(2)
From equation (1) and (2), we get
e=−LdIdt. . . . . . . . .(3)
The self induced emf is also called back emf, as it opposes any change in the current. So, work needs to be done against back emf in the establishing current and this work done is stored as magnetic potential energy.
The rate of doing work is,
dWdt=|e|I=LIdIdt
The total work done,
W=∫dW=∫I0LIdI
W=12LI2
b)
(i) The direction of induced current in the loop is clockwise.
Given,
d=20cm
v=20cm/s
The current will persist till the entire loop comes out of the field,
t=dv=2020=1sec
(ii) The maximum flux is, ϕ=Bla, a=side of the square.
The magnetic flux remains constant inside the magnetic field. This flux will starts dropping once the loop comes out of the magnetic field and it is zero when it comes completely out from the magnetic field as shown in the above figure.
The maximum Induced emf in coil is, e=−dϕdt=−Blv
The e remains constant till the entire comes out from the magnetic field, when it comes out then emf drops to zero as shown in the above figure.