wiz-icon
MyQuestionIcon
MyQuestionIcon
12
You visited us 12 times! Enjoying our articles? Unlock Full Access!
Question

DEFINITION VALID FOR SINGLE ELECTRON SYSTEM:
Ground state: Lowest energy state of any atom or ion is called ground state of the atom. It is n=1.
Excited energy (IE): Minimum energy required to move an electron from ground state to n= is called ionisation energy of the atom or ion.
Ionisation Potential (I.P): Potential difference through which a free electron must be accelerated from rest, such that its kinetic energy becomes equal to ionisation energy of the atom is called ionisation potential of the atom.
Excitation Energy: Energy required to move an electron from ground state of the atom to any other state of the atom is called excitation energy of that state.
Excitation Potential: Potential difference through which an electron must be accelerated from rest to so that its kinetic energy become equal to excitation energy of any state is called excitation potential of that state.
Binding Energy 'or' Separation Energy: Energy required to move an electron from any state to n=is called binding energy of the state.
The wavelength of the photon emitted upon an electronic transition from n2 to n1 orbit in a H-like species is given by the formula:
1λ=RZ2(1n211n22)

Now answer the following question:
If the binding energy of II excited state of a H-like species is 13.6 eV then:

A
The atomic number Z of given H-like species is 2.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
A photon of energy 30 eV can ionise an electron form I excited state of given H-like species.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
Upon de-excitation from n=4 to n=2 in given H-like species, the emitted photon has wavenumber =3R16 (R=Rydberg's constant)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Ionisation potential of given H-like species is 122.4V.
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D Ionisation potential of given H-like species is 122.4V.
n=3
Binding energy of II excited state =13.6×Z2n2=13.6eV

So Z=3 ; Atomic number of H like species is 3

lonisation potential=13.6Z2=13.6×32=122.4eV.

A photon of energy 30 eV can not ionise an electron form I excited state of given H-like species.

Option D is correct.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Emission and Absorption Spectra
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon