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DEFINITION VALID FOR SINGLE ELECTRON SYSTEM:
Ground state: Lowest energy state of any atom or ion is called ground state of the atom. It is n=1.
Excited energy (IE): Minimum energy required to move an electron from ground state to n= is called ionisation energy of the atom or ion.
Ionisation Potential (I.P): Potential difference through which a free electron must be accelerated from rest, such that its kinetic energy becomes equal to ionisation energy of the atom is called ionisation potential of the atom.
Excitation Energy: Energy required to move an electron from ground state of the atom to any other state of the atom is called excitation energy of that state.
Excitation Potential: Potential difference through which an electron must be accelerated from rest to so that its kinetic energy become equal to excitation energy of any state is called excitation potential of that state.
Binding Energy 'or' Separation Energy: Energy required to move an electron from any state to n=is called binding energy of the state.
The wavelength of the photon emitted upon an electronic transition from n2 to n1 orbit in a H-like species is given by the formula:
1λ=RZ2(1n211n22)

Now answer the following question:
If the binding energy of II excited state of a H-like species is 13.6 eV then:

A
The atomic number Z of given H-like species is 2.
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B
A photon of energy 30 eV can ionise an electron form I excited state of given H-like species.
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C
Upon de-excitation from n=4 to n=2 in given H-like species, the emitted photon has wavenumber =3R16 (R=Rydberg's constant)
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D
Ionisation potential of given H-like species is 122.4V.
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Solution

The correct option is D Ionisation potential of given H-like species is 122.4V.
n=3
Binding energy of II excited state =13.6×Z2n2=13.6eV

So Z=3 ; Atomic number of H like species is 3

lonisation potential=13.6Z2=13.6×32=122.4eV.

A photon of energy 30 eV can not ionise an electron form I excited state of given H-like species.

Option D is correct.

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