Degree of dissociation of 0.1 M CH3COOH is (Given Ka(CH3COOH)=1×10−5):
Calculate the emf of the cell
Pt, H2(1.0atm) | CH3COOH (0.1M) || NH3(aq, 0.001M) | H2(1.0 atm), Pt Ka(CH3COOH) = 10−5, Kb(NH3) = 10−5