Degree of - 2- dydx 2 -3-2-ad2ydx2 is-

The correct option is C 2 (2+y_1^2)^3=a^2 y_2^2 ⇒ order=2 degree=2 ...

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Degree of a Differential Equations

Degree of [...

Question

Degree of ${[2 + {(\frac{d y}{d x})}^{2}]}^{3 / 2} = a \frac{d^{2} y}{d x^{2}}$ is:

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{[5 + {(\frac{d y}{d x})}^{2}]}^{3 / 2} = 6 \frac{d^{2} y}{d x^{2}}

Find the order and degree of the differential equation $\sqrt{1 - {(\frac{d y}{d x})}^{2}} = a {(\frac{d^{2} y}{d x^{2}})}^{\frac{1}{3}}$ .

{[1 + {(\frac{d y}{d x})}^{2}]}^{3 / 2} = 8 \frac{d^{2} y}{d x^{2}}

{(\frac{d y}{d x})}^{2} + 3 \frac{d^{2} y}{d x^{2}} = \sqrt{1 + {(\frac{d y}{d x})}^{2}}

{(\frac{d^{4} y}{{d x}^{4}} + \frac{d^{2} y}{{d x}^{2}})}^{5 / 2} = a \frac{d^{2} y}{{d x}^{2}}

p, q

p + q =

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