Degree of - d2ydx2- dydx 2 -3-2-kd2ydx2 is-

The correct option is B 3 (y_2+y_1^2)^3=k^2y_2^2 ⇒ y_2^3+y_1^6+3y_1^2y_2(y_2+y_1^2)=k^2y_2^2 ⇒ Order=2 degree=3 ...

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Order of a Differential Equation

Degree of [...

Question

Degree of ${[\frac{d^{2} y}{d x^{2}} + {(\frac{d y}{d x})}^{2}]}^{3 / 2} = k \frac{d^{2} y}{d x^{2}}$ is:

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\frac{d^{2} y}{d x^{2}} + {[1 + {(\frac{d y}{d x})}^{2}]}^{\frac{3}{2}} = 0

{[\frac{d^{2} y}{d x^{2}} + {(\frac{d y}{d x})}^{2}]}^{1 / 2} = \frac{d^{3} y}{d x^{3}}

\frac{d^{2} y}{d x^{2}} + 3 {[\frac{d y}{d x}]}^{2} = x^{2} l o g [\frac{d^{2} y}{d x^{2}}]

\frac{d^{2} y}{d x^{2}} = {[1 + {(\frac{d y}{d x})}^{2}]}^{3 / 2}

The degree of the differential equation is

[Pb. CET 2004]

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